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Pi-Bond Oxidations

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Syn-hydroxylation

With OsO4

In syn-hydroxylation, an alkene is turned into a 1,2-diol, a glycol. This is another example of “Giving it the horns.” In this case, osmium tetroxide (OsO4) acts like the bull with two oxides as the horns. Osmium tetroxide reacts with the pi-bond of the alkene to make an osmate ester. The osmate ester can be oxidized with hydrogen peroxide and hydroxide to make a glycol with syn-stereochemistry. The bull has given it the horns. OsOis a catalyst in this reaction. The reaction starts with OsO4 and ends with OsO4. Since it is regenerated, only a small amount is needed in this reaction.

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One drawback of this reaction is that OsO4 is expensive, toxic, and volatile. Volatile means it easily evaporates. This is especially problematic if that compound is toxic!

With KMnO4

KMnO4 hydroxylation

A safer, cheaper, and easier method to perform a syn-hydroxylation is to a cold, dilute, sometimes neutral aqueous solution of potassium permanganate (KMnO4). The active species is the permanganate (MnO4-). The permanganate acts like the bull and uses its oxides as horns. The mechanism is similar to the reaction with OsO4. In this case, a manganate ester is formed. Following the addition of water and hydroxide, a glycol is formed with syn-stereochemistry.


Potassium permanganate is not a catalyst because it is not regenerated in this reaction. It is reduced.  Notice, in the reaction with OsO4, the oxidizer H2O2 is used to add more oxygen atoms to regenerate the OsO4 catalyst. In the reaction with KMnO4, no oxidizer is used. That is why the KMnO4 is not a catalyst. This is OK since KMnO4 is so cheap.

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Potassium permanganate is a quick and easy chemical test for alkenes. Aqueous potassium permanganate is a purple solution. We know that it reacts with alkenes. If an unknown organic compound is added to the purple potassium permanganate and nothing happens, we could reason that the unknown organic compound is NOT an alkene. On the other hand, if the purple potassium permanganate solution turns brown, we would know a reaction occurred because the brown MnO2 was formed and the unknown organic compound that was added must be an alkene. 

KMnO4 oxidation of alkynes

KMnO4 oxidation of alkynes

The same reaction can happen with the two pi-bonds of an alkyne. Since there are two pi-bonds, the dihydroxylation can happen twice, resulting in a species with four hydroxyl groups on it. This is unstable. Two water molecules are eliminated resulting in an α-diketone (alpha-diketone). Under neutral KMnO4 conditions, the α-diketone is the product.

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kmn2.png

The double dihydroxylation of the alkyne makes sense. Look closely how the two molecules of water are lost leaving only two oxygen atoms behind on neighboring carbon atoms.

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Further oxidation with KMnO4

warm KMnO4 alkenes

Of alkenes

If the alkene reaction with potassium permanganate is not conducted under dilute and cold conditions but is instead run under more basic conditions and warm and concentrated conditions, further oxidation can occur. When the glycol is further oxidized, the carbon-carbon sigma bond of the glycol is broken and the single carbon-oxygen bonds of the glycol turn into carbon-oxygen double bonds (an oxidation). KMnO4 is a pretty strong oxidizer. If an aldehyde is first made by this oxidation, it is further oxidized to a carboxylic acid.

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and the further oxidation of the glycol with hot, concentrated KMnO4.

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Overall, this reaction can be thought of as chopping the alkene in half and inserting two oxygen atoms. If the result is a ketone, nothing more happens to that carbon atom. If the result is an aldehyde, further oxidation to a carboxylic acid occurs.

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Of alkynes

warm KMnO4 alkynes

When KMnO4 reacts with an alkyne under more aggressive conditions, in the presence of hydroxide base and heat, the α-diketone is produced like under less aggressive neutral conditions, but it is then further, fully oxidized. The C-C bond between the two carbonyl groups is cleaved followed by further oxidation resulting in two carboxylic acids. With three C-O bonds, the carboxylic acid is fully oxidized and cannot be oxidized further.

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and the further oxidation of the α-diketone with hot, concentrated KMnO4.

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Overall, the cleavage can be thought of as. . .

Screenshot 2024-11-20 at 12.44.11 PM.png

Notice that in this oxidation, three carbon-carbon bonds of the alkyne turn into three carbon-oxygen bonds of the carboxylic acid.

Ozonolysis

Ozonolysis

Of alkenes

Ozonolysis is very similar to oxidation by KMnO4 in warm, concentrated solution. The difference is that if an aldehyde is formed, it is not further oxidized to a carboxylic acid. Notice that in this oxidation, two carbon- carbon bonds of the alkene turn into two carbon-oxygen bonds of the carbonyl.

Screenshot 2024-11-20 at 12.47.54 PM.png

The mechanism for this reaction does not really help us learn the reaction. If you are interested in it, you can look it up elsewhere. Ozone is a compound with three oxygen atoms (O3). Two of the three oxygen atoms are in the final product. The third oxygen atom ends up on the Me2S to make Me2SO.

Of alkynes

The reaction of an alkyne with ozone results in the same products as the full oxidation with KMnO4 under basic, hot conditions. The carbon-carbon triple bond is cleaved and each carbon atom is fully oxidized resulting in two carboxylic acids. Again, notice that in this oxidation, three carbon-carbon bonds of the alkyne turn into three carbon-oxygen bonds of the carboxylic acid.

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10. Draw the products of the following reactions.

a)

b)

c)

Screenshot 2024-11-20 at 12.53.34 PM.png
Screenshot 2024-11-20 at 12.53.39 PM.png
Screenshot 2024-11-20 at 12.53.45 PM.png

d)

Screenshot 2024-11-20 at 12.53.52 PM.png

e)

Screenshot 2024-11-20 at 12.54.02 PM.png

Answers

10.

a)

b)

c)

d)

Screenshot 2024-11-20 at 12.56.54 PM.png
Screenshot 2024-11-20 at 12.56.45 PM.png
Screenshot 2024-11-20 at 12.56.27 PM.png
Screenshot 2024-11-20 at 12.56.18 PM.png

e)

Screenshot 2024-11-20 at 12.57.10 PM.png

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